+176 Bags A, B and C each contain some carrots.
There are a total of 863 carrots.
The ratio of the number of
carrots in bag B to the number of carrots in bag C is 4:3
1/3 of the carrots are removed
from bag A and bag C.
There are now 674 carrots.
How many carrots were in bag A at
the start?
+1693 A + B + C = 863 A => x B => 4y C => 3y
1/3(A) + 1/3(C) = 863 - 674
x/3 + y = 189
x = 3(189 - y)
x = 567 - 3y
(567 - 3y) + 7y = 863
y = 74
x = 345 This is your answer 
