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Bags A, B and C each contain some carrots.

There are a total of 863 carrots.
The ratio of the number of
carrots in bag B to the number of carrots in bag C is 4:3

1/3 of the carrots are removed 

from bag A and bag C.

There are now 674 carrots.

How many carrots were in bag A at 

the start?

 Dec 19, 2021
 #1
avatar+1696 
+4

A + B + C = 863           A => x          B => 4y         C => 3y

 

1/3(A) + 1/3(C) = 863 - 674

 

x/3 + y = 189

 

x = 3(189 - y) 

 

x = 567 - 3y

 

(567 - 3y) + 7y = 863

 

y = 74

 

x = 345      This is your answer  smiley

 Dec 19, 2021

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