Bags A, B and C each contain some carrots.

There are a total of 863 carrots.

The ratio of the number of

carrots in bag B to the number of carrots in bag C is 4:3

1/3 of the carrots are removed

from bag A and bag C.

There are now 674 carrots.

How many carrots were in bag A at

the start?

Whayousayy Dec 19, 2021

#1**+4 **

A + B + C = 863 A => **x **B => **4y **C => **3y**

1/3(A) + 1/3(C) = 863 - 674

x/3 + y = 189

x = 3(189 - y)

**x = 567 - 3y**

**(567 - 3y) + 7y = 863**

**y = 74**

**x = 345 This is your answer **

civonamzuk Dec 19, 2021