+0  
 
0
589
1
avatar

Let \(\sum_{n = 0}^{123456789} \frac{3n^2 + 9n + 7}{(n^2 + 3n + 2)^3} = \frac{a}{b},\) where \(a\) and \(b\) are relatively prime positive integers. Find \(b-a.\)

 Mar 23, 2020
 #1
avatar+33614 
+2

See my reply at https://web2.0calc.com/questions/let-where-and-are-relatively-prime-positive-integers-find#r4 

 Mar 23, 2020

3 Online Users

avatar