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Let \(\sum_{n = 0}^{123456789} \frac{3n^2 + 9n + 7}{(n^2 + 3n + 2)^3} = \frac{a}{b},\) where \(a\) and \(b\) are relatively prime positive integers. Find \(b-a.\)

 Mar 23, 2020
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See my reply at https://web2.0calc.com/questions/let-where-and-are-relatively-prime-positive-integers-find#r4 

 Mar 23, 2020

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