Let abc be an equilateral triangle with side length 1. Point n lies on the side bc such that bc = 2cn. Find the length of an.
Since you need it quick, here you go, rounded to 3 sig figs:
\(\fbox{0.433}\)
ummm..test is over now, can you explain please?
You've got the wrong answer!!!
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AN is the height of triangle ABC.
Angle ANC = 90 degrees
Angle C = 60 degrees
Therefore, AN = sin(60) = 0.866
btw, CN = 0.433
+80 
