The ellipse x^2/49+y^2/b^2=1 has foci at (5,0) and (-5,0).
(a) Fimd the length of a semi major axis of this ellipse
(b)compute the value of b
+130066 x^2/49 + y^2 / b^2 = 1
The center is (0, 0)
c = distance from the center to either focal point = 5
a = sqrt (49) = 7 = length of semi-major axis
b = sqrt (a^2 - c^2 ) = sqrt ( 7^2 - 5^2 ) = sqrt ( 49 - 25 ) = sqrt (24) = 2sqrt (6)
Equation is
x^2/49 + y^2/24 = 1
See the graph here : https://www.desmos.com/calculator/3l1f0moddl
