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The vertices of triangle ABC lie on the sides of equilateral triangle DEF, as shown. If CD = 3, CE = BD = 2, and

 Dec 21, 2021
 #1
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The problem is asking for the length AE.  By the Cosine Law, the answer is 5/3.

 Dec 21, 2021
 #2
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The question is incomplete! cheeky

 

The vertices of triangle ABC lie on the sides of the equilateral triangle DEF, as shown. If CD = 3, CE = BD = 2, and angle ACB = 90º, then find AE.

 Dec 21, 2021

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