The vertices of triangle ABC lie on the sides of equilateral triangle DEF, as shown. If CD = 3, CE = BD = 2, and
The problem is asking for the length AE. By the Cosine Law, the answer is 5/3.
The question is incomplete!
The vertices of triangle ABC lie on the sides of the equilateral triangle DEF, as shown. If CD = 3, CE = BD = 2, and angle ACB = 90º, then find AE.
