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\(0.3 \overline{2} = \dfrac{32}{99}\)

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Let \(x = 0.3 \overline 2 \).

 

This means \(10x = 3. \overline 2\) and \(100x = 32. \overline 2\)

 

Subtracting \(10x \) from \(100x\) gives us: \(90x=29\), because the repeating part cancels each other out. 

 

Can you find the value of x from here?