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# help asap

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The hypotenuse of a right triangle measures 2 sq root 15 centimeters and its shorter leg measures 2 sq root 6 centimeters.  What is the measure of the larger acute angle of the triangle?  Round your answer to the nearest tenth of a degree.

Mar 8, 2020

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Explanation:

Obviously, by Pythagorean Theorem, the longer leg is 6.

Longer leg is opposite larger angle.

We can use law of cosines to get $$6^2=(2\sqrt{15})^2+(2\sqrt{6})^2-2 \times (2\sqrt{15})\times (2\sqrt6) \times \cos{\theta}$$

Simplifying, $$-48=-24\sqrt{10} \times \cos{\theta}$$, so $$\frac{\sqrt{10}}{5}=\cos{\theta}$$.

Assuming you can use a calculator, use inverse cosine function to get $$\theta \approx 50.7685 \circ$$, and rounding to the nearest tenth, the angle is 50.8 degrees.

You are very welcome!

:P

Mar 8, 2020