If \(0.8= \frac{y}{186+x}\), find the smallest value of x, if x and y are positive integers.
a=1; b=1;d=b / (a+186); if(d==0.8, goto4, goto5);printa, b; a++;if(a<1000, goto2, 0);a=1;b++;if(b<1000, goto2, discard=0;
OUTPUT: x = 4 and y = 152
