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If \(0.8= \frac{y}{186+x}\), find the smallest value of x, if x and y are positive integers.

 Sep 29, 2020
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a=1; b=1;d=b / (a+186); if(d==0.8, goto4, goto5);printa, b; a++;if(a<1000, goto2, 0);a=1;b++;if(b<1000, goto2, discard=0; 

 

OUTPUT: x = 4    and    y = 152

 Sep 29, 2020

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