HELP BEFORE TOMORROW PLEASe

cos(pi-x) +sin(x-pi/2) = 1

Solve for all answers between 0-2pi

$cos(pi-x) +sin(x-pi/2) = 1\\ -cosx+sinxcos\pi/2-cosxsin\pi/2=1\\ -cosx+0-cosx=1\\ -2cosx=1\\ cosx=-0.5\\ \text{x is in the 2nd or third quad}\\ \text{First quad }\pi/3\\ x=\frac{2\pi}{3}\quad or \quad x=\frac{4\pi}{3}$