We can simplify the given expression to: \(a = 105 (\mod 11)\)
This means that the remainder of a when divided by 11 is 105.
However, we can simplify this furthur, because 105 can "go" into 11 9 times, with a final remainder of 6.
This means that \(a = 6 (\mod 11)\).
Can you find the remainder from here?