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What is the exact value of x in the exponential equation 25x − 57 = 43 

 Dec 6, 2018
 #1
avatar+5797 
+1

\(25^x - 57 = 43\\ 25^x = 100\\ 5^{2x} = 100\\ 2x\log(5) = \log(100) = 2\\ x = \dfrac{1}{\log(5)}\)

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 Dec 6, 2018
 #2
avatar+18965 
+2

Another possibility

25^x = 43 + 57

25^x = 100

x log 25 = 2

x = 2/log25    (same thing)

 Dec 7, 2018

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