I tried two of them but I don't think they are right. The other ones, I'm confused on how to answer them. Please help explain! Thank you.

Guest Jan 23, 2019

#1**+1 **

The object is to get x by itself..then ......"swap" x and y .

y = 3x + 2 subtract 2 from both sides

y - 2 = 3x divide both sides by 3

[ y - 2 ] / 3 = x "swap" x and y

[ x - 2 ] / 3 = y so.....the inverse is in red....your answer is correct !!!

y = (2/3)x - 5

y + 5 = (2/3)x mltiply both sides by (3/2)

(3/2y + 15/2 = x

(3/2)x + 15/2 = y the inverse is in red

y = x^2 + 8 your answer is good !!!!

y = ( x + 3)^2 tke both roots

±√y = x + 3

±√y - 3 = x

±√x - 3 = y the inverse is in red

y = √ [ 2x - 3 ] square both sides

y^2 = 2x - 3

y^2 + 3 = 2x

[ y^2 + 3 ] / 2 = x

[ x^2 + 3 ] / 2 = y the inverse is in red

y = √[4x] - 7

y + 7 = √[4x] square both sides

(y + 7)^2 = 4x divide both sides by 4

(y + 7)^2 / 4 = x

(x + 7)^2 / 4 = y the inverse is in red

CPhill Jan 23, 2019