+0  
 
0
181
1
avatar

I tried two of them but I don't think they are right. The other ones, I'm confused on how to answer them. Please help explain! Thank you.

 Jan 23, 2019
 #1
avatar+107405 
+1

The object is to get x by itself..then ......"swap" x and y  .

 

y = 3x + 2     subtract 2 from both sides

 

y - 2  = 3x       divide both sides by 3

 

[ y - 2 ] / 3  =  x       "swap" x and y

 

[ x - 2 ] / 3  =  y        so.....the inverse is in red....your answer is correct  !!!

 

 

 

y = (2/3)x - 5

 

y + 5 =  (2/3)x      mltiply both sides by (3/2)

 

(3/2y + 15/2 =  x

 

(3/2)x + 15/2  =  y        the inverse is in red

 

 

y = x^2 + 8   your answer is good  !!!!

 

 

y = ( x + 3)^2       tke both roots

 

±√y   = x + 3

 

±√y -  3   =  x

 

±√x   -  3   =  y           the inverse is in red

 

 

y = √ [ 2x - 3 ]       square both sides

 

y^2 = 2x - 3

 

y^2 + 3  =  2x

 

[ y^2 + 3 ] / 2  =    x

 

[ x^2 + 3 ] / 2  =  y             the inverse is in red   

 

 

y = √[4x] - 7

 

y + 7 =  √[4x]             square both sides

 

(y + 7)^2 =  4x       divide both sides by 4

 

(y + 7)^2 / 4  =  x

 

(x + 7)^2 / 4  =   y       the inverse is in red

 

 

 

cool cool cool

 Jan 23, 2019

17 Online Users