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What is the equation of a line that passes through the point (-7,2) and is perpendicular to the line whose equation is y = −2/5*x + 8?

 Jun 15, 2021

Best Answer 

 #1
avatar+2266 
+2

Perpendicular line is a negative reciprocal sope. 

-2/5 turns into 5/2. 

 

y = 5/2x + b

2 = 5/2(-7) + b

39/2 = b

 

y = 5/2x + 39/2

 

=^._.^=

 Jun 15, 2021
 #1
avatar+2266 
+2
Best Answer

Perpendicular line is a negative reciprocal sope. 

-2/5 turns into 5/2. 

 

y = 5/2x + b

2 = 5/2(-7) + b

39/2 = b

 

y = 5/2x + 39/2

 

=^._.^=

catmg Jun 15, 2021

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