What is the equation of a line that passes through the point (-7,2) and is perpendicular to the line whose equation is y = −2/5*x + 8?
Perpendicular line is a negative reciprocal sope.
-2/5 turns into 5/2.
y = 5/2x + b
2 = 5/2(-7) + b
39/2 = b
y = 5/2x + 39/2
=^._.^=