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In how many ways can 8 people be seated in a row of chairs if three of the people, John, Wilma and Paul, refuse to sit in three consecutive seats?

mathtoo Aug 25, 2018

#1**+2 **

The total arrangements possible = 8!

Now...let's consider the arrangements possible if all three DO sit together [in consecutive seats ]

Considering them as a single entity....they can be arranged as 3! = 6 ways

And they can be seated in any 6 positions [ positions 1 - 6 ] = 6 ways

And for each of these arrangements the other people can be seated in 5! = 120 ways

So...the total arrangements possible if they DON'T sit together =

Possible arrangements - Arrangements where they sit together =

8! - [ 6 * 6 * 5!] =

40320 - 36*120 =

40320 - 4320 =

36000 ways

CPhill Aug 25, 2018