How many ways are there to put 5 balls in $4$ boxes if the balls are not distinguishable but the boxes are?
Let k be the number of balls and n be the number of boxes
Assumig no restrictions ( boxes may be empty) the number of ways =
C ( k + n - 1 , n - 1) =
C ( 8 , 3 ) = 56 ways
I think you would do 5!(4) or something to that effect.