+0  
 
0
84
2
avatar

How many ways are there to put 5 balls in $4$ boxes if the balls are not distinguishable but the boxes are?

 Jul 24, 2021

Best Answer 

 #2
avatar+121047 
+1

Let  k  be  the  number of balls    and  n  be  the  number of boxes

 

Assumig no restrictions  ( boxes may be  empty)  the  number of  ways   =

 

C   ( k + n - 1 , n - 1)   =

 

C  ( 8 , 3 )   =     56  ways

 

cool cool cool

 Jul 24, 2021
 #1
avatar+105 
+1

I think you would do 5!(4) or something to that effect.

 Jul 24, 2021
 #2
avatar+121047 
+1
Best Answer

Let  k  be  the  number of balls    and  n  be  the  number of boxes

 

Assumig no restrictions  ( boxes may be  empty)  the  number of  ways   =

 

C   ( k + n - 1 , n - 1)   =

 

C  ( 8 , 3 )   =     56  ways

 

cool cool cool

CPhill Jul 24, 2021

27 Online Users

avatar