How many three digit odd numbers can be formed from the digits 1, 2, 3, and 4, if digits can be repeated?

Guest Jul 31, 2021

#1**+1 **

How many ways to chose the units digit?

how many ways to choose the tens digit?

how ways to choose the hundreds digit?

multiply the answers together.

Melody Jul 31, 2021

#2**+1 **

Melody: They want "**How many three digit ODD numbers**" :

111 ( 1 ) , 113 ( 3 ) , 123 ( 6 ) , 133 ( 3 ) , 223 ( 3 ) , 233 ( 3 ) , 333 ( 1 ) >>Total combinations = 7

>>Total permutations =**20 [Numbers in parentheses]**

Guest Jul 31, 2021

#3**+2 **

For ODD 3 digit integers

4 choices for first digit

4 choices for second digit

two choices for third digit ( 1 or 3) = 4 x 4 x 2 = 32 three digit ODD numbers

ElectricPavlov Jul 31, 2021