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How many three digit odd numbers can be formed from the digits 1, 2, 3, and 4, if digits can be repeated?

 Jul 31, 2021
 #1
avatar+114511 
+1

How many ways to chose the units digit?

how many ways to choose the tens digit?

 how ways to choose the hundreds digit?

 

multiply the answers together.

 Jul 31, 2021
 #2
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+1

Melody: They want "How many three digit ODD numbers" :

 

111 ( 1 ) ,  113 ( 3 ) , 123 ( 6 ) , 133 ( 3 ) , 223 ( 3 ) , 233 ( 3 ) , 333 ( 1 ) >>Total combinations = 7
>>Total permutations =20 [Numbers in parentheses]

 Jul 31, 2021
 #5
avatar+114511 
+1

Hi Guest,

 

It has asked for a three digit, odd number.

 

Not a number with 3 odd digits.   

 

That is how EP and I have interpreted it anyway.

Melody  Aug 1, 2021
 #3
avatar+34388 
+2

For ODD 3 digit integers

   4 choices for first digit

   4 choices for second digit

   two choices for third digit ( 1 or 3) =   4 x 4 x 2 = 32   three digit ODD numbers

 Jul 31, 2021
 #4
avatar+114511 
+1

Thanks EP and also guest.

 

EP has done what I suggested.

 

there are 2 numbers, (1 and 3) that could go in the units place

then there are 4 that can go in the tens and 4 that can go in the hundreds

 

2*4*4 = 32

Melody  Aug 1, 2021

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