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For what ordered pair \((a,b)\) are there infinite solutions \((x,y)\) to the system

 

\(\begin{align*} 4x+ay&=-8,\\ 2x+y&=b. \end{align*}\)

 Jan 2, 2020

Best Answer 

 #2
avatar+111321 
+1

To have infinite solutions ...... let the first equation  be a multiple of 2  of the second equation

 

So   2  [ 2x + y  =  b]    =   4x   +  2y   = 2b 

 

a =  2     and    2b = -8   so    b  = -4

 

So

 

(a,b)   =  (2, -4)

 

 

 

cool  cool  cool

 Jan 2, 2020
 #1
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0

(a,b) = (4,-1).

 Jan 2, 2020
 #2
avatar+111321 
+1
Best Answer

To have infinite solutions ...... let the first equation  be a multiple of 2  of the second equation

 

So   2  [ 2x + y  =  b]    =   4x   +  2y   = 2b 

 

a =  2     and    2b = -8   so    b  = -4

 

So

 

(a,b)   =  (2, -4)

 

 

 

cool  cool  cool

CPhill Jan 2, 2020

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