Find the complex number z that satisfies (1+i)z-2*conjugate of z* = -11+25i

I don't understand how this works, I tried distributing z and got z+zi-2*conjugate of z* = -11+25i, then I subtracted z+zi from both sides and got -2*conjugate of z* = -11+25i-z-zi. I had no idea what to do from there.

Guest Dec 15, 2019