Find the complex number z that satisfies (1+i)z-2*conjugate of z* = -11+25i
I don't understand how this works, I tried distributing z and got z+zi-2*conjugate of z* = -11+25i, then I subtracted z+zi from both sides and got -2*conjugate of z* = -11+25i-z-zi. I had no idea what to do from there.
+33614 Let z = a + ib where a and b are real, so that conjugate of z = a - ib.
Put these in your equation, and multiply out the terms, then separately equate real and imaginary parts on both sides of the equation to get two simultaneous equations that you can solve to find a and b.
