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1. There were ninety days in the season. if the ratio of rainy days to clear days was 2 to 13, how many rainy days were there?

 

2. Write all prime factors of 273

 

3. Find the greatest common factor of 6a^3b^2c^10+20c^10-8a^3b^2c^9

 

4. The congregation in the church consisted of adults and children in the ratio of 3 to 7. If there were 105 adults, how many children were there?

 Jan 13, 2017
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2) -  273 = 3 * 7 * 13

 

1) - 2/(2+13) x 90 =12 rainy days

 

4) - 7/3 x 105 =245 children

 

3) - GCF =6 a^3 b^2 c^10 - 8 a^3 b^2 c^9 + 20 c^10

 Jan 13, 2017

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