The height of a ball when it is thrown off a cliff can be represented by the equation $h=45-7t-6t^2$, where $t$ is time in seconds. In how many seconds will the ball reach a height of 25 feet?
We need to solve this
-6t^2 - 7t + 45 = 25
-6t^2 -7t + 20 = 0
(-2t - 5) ( 3t - 4) = 0
Only the econd factor produces a positive result for t
3t - 4 = 0
3t = 4
t = 4/3 seconds
