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Which number a would result in (x-4) being a factor of x^2+ax-8

need it urgently helppp

 Sep 25, 2019
 #1
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x^2 + ax  - 8

 

Notice that since (x - 4)  is a factor   and the last term of the polynomial  is -8......the other factor must be (x + 2)

 

So

 

(x - 4) (x + 2)  = 

 

x^2 -4x + 2x  - 8   =   

 

x^2 -2x - 8

 

So

 

-2x  = ax

 

-2  = a

 

So  "a"  must be  - 2

 

 

 

cool cool cool

 Sep 25, 2019

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