Which number a would result in (x-4) being a factor of x^2+ax-8
need it urgently helppp
x^2 + ax - 8
Notice that since (x - 4) is a factor and the last term of the polynomial is -8......the other factor must be (x + 2)
So
(x - 4) (x + 2) =
x^2 -4x + 2x - 8 =
x^2 -2x - 8
-2x = ax
-2 = a
So "a" must be - 2
