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Let \(\mathbf{P}\) be the \(2\times 2\) matrix that projects vectors onto \(\mathbf{u} = \begin{pmatrix}2\\ -1 \end{pmatrix}\). That is, \(\mathbf{P} \bold{v} = \operatorname{proj}_{\bold{u}} (\bold{v}) = \text{Projection of $\mathbf{v}$ onto $\mathbf{u}$}\)
Use your answers from part (a) to figure out \(\mathbf{P}\).

 Feb 19, 2019
 #1
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The matrix is \(\begin{pmatrix} 1/9 & -2/9 \\ 2/9 & 4/9 \end{pmatrix}\).

 Dec 1, 2019

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