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Use the picture below to calculate the projection of $\mathbf{v}$ onto $\mathbf{u}$:

 Feb 9, 2019

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 #1
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\(\vec{u}=(3,1)\\ \vec{v} = (2,4)\\ p_{\vec{u}}(\vec{v}) = \dfrac{\vec{v}\cdot \vec{u}}{|\vec{u}|^2}\vec{u} = \\ \dfrac{(3,1)\cdot(2,4)}{|(3,1)|^2} \vec{u}= \dfrac{10}{10}(3,1) =(3,1)\)

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 Feb 9, 2019
 #1
avatar+6248 
+2
Best Answer

\(\vec{u}=(3,1)\\ \vec{v} = (2,4)\\ p_{\vec{u}}(\vec{v}) = \dfrac{\vec{v}\cdot \vec{u}}{|\vec{u}|^2}\vec{u} = \\ \dfrac{(3,1)\cdot(2,4)}{|(3,1)|^2} \vec{u}= \dfrac{10}{10}(3,1) =(3,1)\)

Rom Feb 9, 2019

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