+0  
 
0
122
1
avatar

Find the focus of the parabola \(x = -\frac{1}{12} y^2\).

 Mar 2, 2021
 #1
avatar+34316 
+1

If you have the equation of a parabola in vertex form x=a(y-k )2+ h, then the vertex is at (k,h) and the focus is (k+1/4a, h).

 

you have   x = -1/12 (y-0)^2   + 0       vertex is thus    0,0       a = -1/12

                                                                                        focus is thus      ( 1/(4*-1/12), 0   =  -3,0

 Mar 2, 2021

15 Online Users

avatar
avatar