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# HELP FASt

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Find the focus of the parabola $$x = -\frac{1}{12} y^2$$.

Mar 2, 2021

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If you have the equation of a parabola in vertex form x=a(y-k )2+ h, then the vertex is at (k,h) and the focus is (k+1/4a, h).

you have   x = -1/12 (y-0)^2   + 0       vertex is thus    0,0       a = -1/12

focus is thus      ( 1/(4*-1/12), 0   =  -3,0

Mar 2, 2021