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$$\left(\frac{(1^2)^3}{2^3}\right)^2$$

Guest Apr 26, 2017
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well, remember G.E.M.S.

G= grouping. grouping is first, so do 1^2 first= 1

E= exponants. exponants are howmany times you multiply a number by itself. so 1^3 is still 1

M= multiplication, or it's opposit, division. so 1/(2^3) =1/8

S= subtract or add. there are none here, but remember this! (1/8)^2 is the acctuall problem.

oh, and by the way, your welcome.

Guest Apr 26, 2017

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