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Evaluate $\lfloor \sqrt{1} \rfloor + \lfloor \sqrt{2} \rfloor + \lfloor \sqrt{3} \rfloor + \dots + \lfloor \sqrt{25} \rfloor$.

 
 Jul 31, 2022

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 #2
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listfor(n, 1,25, floor(2#(n)):

 

(1, 1, 1, 2, 2, 2, 2, 2, 3, 3, 3, 3, 3, 3, 3, 4, 4, 4, 4, 4, 4, 4, 4, 4, 5)==75

 
 Aug 1, 2022
 #1
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0

The sum is 153.

 
 Aug 1, 2022
 #2
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+1
Best Answer

listfor(n, 1,25, floor(2#(n)):

 

(1, 1, 1, 2, 2, 2, 2, 2, 3, 3, 3, 3, 3, 3, 3, 4, 4, 4, 4, 4, 4, 4, 4, 4, 5)==75

 
Guest Aug 1, 2022

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