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Find the area of an isosceles triangle with two legs of length 8 and base of length 4.

 Jun 22, 2021
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Height  =   sqrt  (   8^2  -  2^2)   =  sqrt  (60)  =   2sqrt (15)

 

Area  =    (1/2)  (4)  ( 2 sqrt (15) )  =  4 sqrt (15)  ≈   15.49  

 

 

cool cool cool

 Jun 22, 2021

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