Drag and drop a statement or reason to each box to complete the proof.
Given: parallelogram EFGH
Prove: EG¯¯¯¯¯ bisects HF¯¯¯¯¯¯ and HF¯¯¯¯¯¯ bisects EG¯¯¯¯¯ .
Definition of a Parallelogram
EF = HG
EK = GK
FK = HK
Definition of bisector
EF¯¯¯¯¯ ∥ HG¯¯¯¯¯¯ = Definition of a parallelogram
? = When two parallel lines are cut by a transversal, alternate interior angles are congruent.
EF¯¯¯¯ ≅ HG¯¯¯¯ = The opposite sides of a parallelogram are congruent.
△EKF≅△GKH = ASA Congruence Postulate
EK¯¯¯¯ ≅ GK¯¯¯¯ =CPCTC
FK¯¯¯¯ ≅ HK¯¯¯¯
EG¯¯¯¯ bisects HF¯¯¯¯ nad HF¯¯¯¯ bisects EG¯¯¯¯ = Def. of bisector
Where the REASON says: When two parallel lines are cut by a transversal, alternate interior angles are congruent.
Which STATEMENT would it be?:
(A) ∠EKF ≅ ∠HKF
(B) ∠FEK ≅ ∠HGK
∠EFK ≅ ∠GHK
AH!!!!....this site does NOT LIKE the use of too many "<" signs....I don't know why, but it cut off my answer....!!!!!
The answer is
angle FEK = angle HGK
angle EFK = angle GHK
Sorry...."Ghosts in the machine "