Point D is on side AC of triangel ABC such that angle ADB = angle ABD and angle ABC - angle ACB = 37 degrees. Find angle DBC in degrees.
+1639 Point D is on side AC of triangle ABC such that angle ADB = angle ABD and angle ABC - angle ACB = 37 degrees. Find angle DBC in degrees.
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Let triangle ABC be the right triangle.
∠B + ∠C = 90º ∠ABD = ∠ADB = 45º
∠B = ∠C + 37 ∠C = x
x + 37 + x = 90 x = 26.5
∠DBC = ∠B - ∠ABD = 18.5º
