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In isosceles right triangle ABC, shown here, AC=BC. Point X is on side BC such that CX=6 and XB=12, and Y is on side AB such that $\overline{XY}\perp\overline{AB}$. What is the length AX?

 

 Jul 11, 2021
 #1
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AX = sqrt(AC2 + CX2)

 

That was easy.

 

What's the length of CY?

 Jul 11, 2021
edited by Guest  Jul 11, 2021

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