In isosceles right triangle ABC, shown here, AC=BC. Point X is on side BC such that CX=6 and XB=12, and Y is on side AB such that $\overline{XY}\perp\overline{AB}$. What is the length AX?

Guest Jul 11, 2021

#1**+1 **

AX = sqrt(AC^{2} + CX^{2})

That was easy.

What's the length of CY?

civonamzuk Jul 11, 2021

edited by
Guest
Jul 11, 2021