In isosceles right triangle ABC, shown here, AC=BC. Point X is on side BC such that CX=6 and XB=12, and Y is on side AB such that $\overline{XY}\perp\overline{AB}$. What is the length AX?
+1694 AX = sqrt(AC2 + CX2)
That was easy.
What's the length of CY?
