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In the diagram, a semicircle is centered at O, and AB is tangent to the semicirlce at B.  Find BCD, in degrees.

 

 May 2, 2022

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 #1
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If AB is tangent to the semicircle, angle(CBA) = 90o.

 

In triangle(ABC), angle(C) = 30o.

 May 2, 2022
 #1
avatar+23183 
+1
Best Answer

If AB is tangent to the semicircle, angle(CBA) = 90o.

 

In triangle(ABC), angle(C) = 30o.

geno3141 May 2, 2022

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