In square ABCD, P is on BC such that BP = 4 and PC = 1, and Q is on line CD such that DQ = 4 and QC = 1. Find sin angle PBQ.
tan CBQ = (1/5)
sin CBQ = sin PBQ = 1 / sqrt [ 1^2 + 5^2 ] = 1 / sqrt (26) = sqrt (26) / 26
