A right triangle has legs of length 6 and b, and a hypotenuse of length c. The perimeter of the triangle is \(20\). Compute c.
a = 6
a2 + b2 = c2 ---> 62 + b2 = c2 ---> 36 + b2 = c2
a + b + c = 20 ---> 6 + b + c = 20 ---> b + c = 14 ---> b = 14 - c
36 + (14 - c)2 = c2 ---> 36 + 196 - 28c + c2 = c2 ---> 232 - 28c = 0
---> 28c = 232 ---> c = 58/7
Correct
