Triangle ABC has its vertices A, B, and C on the sides of a rectangle 4 units by 5 units as shown. What is the area of the triangle in square units?
+191 There are more than one way to tackle this problem but I'll offer my best solution.
Total area of rectangle = 4*5 = 20
Then, subtract the three white parts that are not counted(2*4/2 = 4, 2*3/2 = 3, and 2*5/2 = 5)
Our final answer is 20 - 3 - 4 -5 = 8
+191 There are more than one way to tackle this problem but I'll offer my best solution.
Total area of rectangle = 4*5 = 20
Then, subtract the three white parts that are not counted(2*4/2 = 4, 2*3/2 = 3, and 2*5/2 = 5)
Our final answer is 20 - 3 - 4 -5 = 8
