P is hte midpoint of BD, AP = BP = 4, AP perp BD, BD perp DC, AB perp BC. In simplest form, what is the area of pentagon ABCDP?
\(\phantom{perimeter of pentagon ABCDP}\)
Area of APB = (1/2) 4^2 = 8
BD = 2*BP = 2*4 = 8
And snce angle DBC = 45°, then BD = Dc
So
Area of BDC = (1/2)(8^2) = 32
Area of ABCDP =
8 + 32 =
40
