In triangle ABC, AB = 10, BC = 4, and angle ABC = 135 degrees. Find the area of triangle ABC
When we have this situation..
Area = (1/2) ( product of sides between the included angle) * sine (included angle)
See what you come up with....if you get stuck....let me know
So...is it 20/(sqrt(2))?
Hey...you got it !!!!
THANK YOU
+118 
