In the figure below, \(D\)is a point on segment \(\overline{CE}\) such that \(\overline{AD}\parallel\overline{BE}\) and \(A\) is not on \(\overline{BC}. \)
Line segments \(\overline{AD}\) and \(\overline{BC}\) intersect at \(P.\)
https://latex.artofproblemsolving.com/5/c/a/5ca5a369cc108d2079bce7ee6ef51af69b30df3a.png
Can \(\angle CAD=\angle CBE?\)
