A triangle has side lengths of 10, 24, and 26. Let a be the area of the circumcircle, and let b be the area of the triangle. Compute a - b in terms of pi.
We have a 10- 24 - 26 right triangle
Area = 10 * 24 / 2 = 120
Circumcenter is at the midpoint of the hypotenuse and the circumradius = 26/ 2 = 13
So area of circumcircle = pi * 13^2 = 169 pi
a - b =
169 pi - 120
