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A right triangle has legs of length  6 and b, and a hypotenuse of length c. The perimeter of the triangle is 15. Compute c.

 Jun 17, 2021
 #1
avatar+366 
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6+b+c = 15

b+c = 15

b = 15 - c

 

6^2 + b^2 = c^2

 

plug in b:

 

6^2 + (15-c)^2 = c^2

36+225+c^2-30c = c^2

 

cancel out the c^2 and combine constants

 

261 - 30c = 0

30c = 261

 

c = 261/30

 

:)

 Jun 18, 2021
 #2
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Badada, seeing as 6 + b + c = 15, then   

shouldn't the second line be  b + c = 9 ?  

After subtracting 6 from both sides.   

Guest Jun 18, 2021
 #3
avatar+1425 
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A right triangle has legs of length  6 and b, and a hypotenuse of length c.                                                                      The perimeter of the triangle is 15. Compute c.

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a = 6             b + c = 9           b = 9 - c           P = 15

 

a2 + b2 = c2

 

62 + (9 - c)2 = c2

 

c = 6.5                (b = 2.5)

 Jun 18, 2021
edited by jugoslav  Jun 18, 2021

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