If altitude CD is sqrt(3) centimeters, what is the number of square centimeters in the area of ACD?
\(\phantom{area of ABC}\)
ADC = 90°
ACD = 60°
AD = sqrt (3) times longer than CD = 3sqrt (3)
Area of ACD = (1/2) (AD) (CD) = (1/2) (3sqrt (3) ) * (3) = (9/2) sqrt (3) cm^2
