Let P be the intersection point of MN and KL, and let x equal MP. You could use the intersecting chord theorem for this problem, but notice that the lines are perpendicular, so we can just use the Pythagorean theorem:
\(12^2+(12+16)^2=x^2\\ x=\sqrt{928}=4\sqrt{58}\)
Since MN is twice that, the answer is \(\boxed{8\sqrt{58}}\)
Let P be the intersection point of MN and KL, and let x equal MP. You could use the intersecting chord theorem for this problem, but notice that the lines are perpendicular, so we can just use the Pythagorean theorem:
\(12^2+(12+16)^2=x^2\\ x=\sqrt{928}=4\sqrt{58}\)
Since MN is twice that, the answer is \(\boxed{8\sqrt{58}}\)
Important:
When two chords intersect inside a circle, then the measures of the segments of each chord multiplied with each other are equal to the product from the other chord.
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LJ = 16
HJ = 40
LJ * HJ = MJ * NJ
640 = MJ * NJ
MN = √2560 or 16√10
If that answer's the best, then what's mine???