Assume that f(3) = 4. Name a point that must be on the graph of y= 4f(2/5*x + 3) - 7.
f(3) = 4
So
(2/5)x + 3 = 3
x = 0
y = 4f ( 3) - 7 =
4 (4) - 7 =
9
(0, 9)
+479 
