help help help

Yeah, rosala....you're correct.....I applied it at the end to convert the decimal to a percent......it should be 100%, though......not just 100...!!!

1102.25=1000(1+r)^2

1.10225=(1+r)^2

Sqrt(1.10225)-1=r

There you go Rosala.

I logged on with my phone just for y.  Can you finish it ?  ☺

I got 4.988%

...but you should do the math also.

No melody I have no idea! Pls can you solve it using this formula

A= P(1+r)^n/100

Melody n will be the years 

1102.25=1000(1+r)^2/100

now pls can you solve it

I'm really thankful to you for logging in for me!

It should not be over 100 rosala.

in my formula r will be a decimal

You will need to change it to a percentage.

The 100 where you have put it is definitely wrong.  😯

1102.25=1000(1+r)^2/100

We don't need the 100, rosala

1102.25=1000(1+r)^2        divide both sides by 1000

1.10225 = (1 + r)^2            take the square root of both sides

1.0499  = 1 + r                   subtract 1 from both sides

.0499 = r    =  about 5%

But 100 is necessary it can't be thrown this is the formula my teacher uses

But why not in the beginning? 

We could have put it at the beginning.....it doesn't matter....

So the formula  is

A= P(1+r)^n x 100%

Yeah thanks! I just found another way do doing it!

 God I'm so scared for this maths exam!

Good luck Rosala,

But you will do fine :)