There is a regular octagon. Each of the eight small circles have centers of midpoints of each side of the octagon. There is one large circle that the eight small circles are inside of. If each of the sides of the octagon are 5 inches, what is the diameter of the large circle? Round your answer, if necessary, to 2 decimal places.
+130540 Looking at 1/8 of the octagon, I'm assuming that we have something like this???
If so.......the small circles will overlap.......the larger enclosing circle will have its center at C and be tangent to the smaller circle at E....thus, its radius = CD + DE = 6.03553 + 2.5 = 8.53553 in. and the diameter will be twice this = about 17.07106 in. or about 17.07 in [rounded]
