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# HELP HELP NOWW

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Let $r$ and $s$ be the roots of $3x^2 + 4x + 12 = 0.$ Find $r^2 + s^2.$

Apr 25, 2020

#1
+21959
+1

Apr 25, 2020
#2
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where?????

Apr 25, 2020
#3
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$$3x^2+4x+12=0$$ Is a quadratic equation of the form $$ax^2+bx+c=0$$ where r and s are roots

By Vieta's formulas:

$$r+s=-\frac{b}{a}$$ Thus $$r+s=-\frac{4}{3}$$

$$r*s=\frac{c}{a}$$ Thus $$rs=4$$

Now notice that:

$$r^2+s^2=(r+s)^2-2rs$$

Substitute

$$(-\frac{4}{3})^2-2(4)=-\frac{56}{9}=-6.22$$

Apr 25, 2020
#4
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it is wrong?????

Apr 26, 2020
#5
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Good, I hope it is, you are too lazy to even lay your question out properly.

And too lazy to search old answers.

I would have preferred that you were not answered at all but if the answer is wrong that is the next best thing.

(No disrespect intended to answering guest, I know you are just trying to help)

Melody  Apr 26, 2020