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Let \(d\) and \(e\) denote the solutions of \(3x^2+10x-25=0.\) Find \((d-e)^2.\)

 Mar 17, 2019
 #1
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\(\quad (d - e)^2\\ = d^2 + e^2 - 2de\\ =(d+e)^2 - 4de\\ =\left(\dfrac{-10}{3}\right)^2 - 4\left(\dfrac{-25}{3}\right)\\ =\dfrac{100}{9} + \dfrac{100}{3}\\ =\dfrac{400}{9}\)

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 Mar 17, 2019
 #2
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Thank you so much

Guest Mar 17, 2019

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