If the roots of the quadratic equation \(\frac32x^2+11x+c=0\) are \(x=\frac{-11\pm\sqrt{7}}{3}\), then what is the value of c?
(3/2)x^2 + 11x + c = 0
Using the discriminant, we have that
(-11)^2 - 4(3/2)c = 7
121 -6c = 7 subtract 121 from each side
-6c = -114 divide both sides by -6
c = -114/-6
c = 19