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If the roots of the quadratic equation \(\frac32x^2+11x+c=0\) are \(x=\frac{-11\pm\sqrt{7}}{3}\), then what is the value of c?

 Oct 4, 2019
 #1
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(3/2)x^2 + 11x + c  = 0

 

Using the discriminant, we have that

 

(-11)^2 -  4(3/2)c   = 7

 

121 -6c =  7      subtract 121 from each side

 

-6c  =  -114   divide both sides by -6

 

c =  -114/-6

 

c = 19

 

cool cool cool

 Oct 4, 2019

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