We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.
 
+0  
 
+1
67
1
avatar

If the roots of the quadratic equation \(\frac32x^2+11x+c=0\) are \(x=\frac{-11\pm\sqrt{7}}{3}\), then what is the value of c?

 Oct 4, 2019
 #1
avatar+104962 
+2

(3/2)x^2 + 11x + c  = 0

 

Using the discriminant, we have that

 

(-11)^2 -  4(3/2)c   = 7

 

121 -6c =  7      subtract 121 from each side

 

-6c  =  -114   divide both sides by -6

 

c =  -114/-6

 

c = 19

 

cool cool cool

 Oct 4, 2019

11 Online Users

avatar