If the roots of the quadratic equation \(\frac32x^2+11x+c=0\) are \(x=\frac{-11\pm\sqrt{7}}{3}\), then what is the value of c?

(3/2)x^2 + 11x + c = 0

Using the discriminant, we have that

(-11)^2 - 4(3/2)c = 7

121 -6c = 7 subtract 121 from each side

-6c = -114 divide both sides by -6

c = -114/-6

c = 19