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Let G be the center of equilateral triangle XYZ. A dilation centered at G with scale factor -3/4 is applied to triangle XYZ, to obtain triangle X'Y'Z'. Let A be the area of the region that is contained in both triangles XYZ and X'Y'Z'. Find A/[XYZ].

 

 

I've squared -3/4 to get 9/16 but didn't work as the answer. i seriously need help thank you

 Jun 8, 2022
 #1
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See https://web2.0calc.com/questions/help_54234

 

I went through the same calculations, and got an answer of 5/12.

 Jun 8, 2022
 #2
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thanks for your reply and i appreciate the effort but it was not correct

 

I went to the same page but It didnt have any calculations on there

Guest Jun 8, 2022

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