A parabola opening up or down has vertex (0,2) and passes through (4,6)
Write its equation in vertex form.
vertex will be the high (mound shaped) or low point (bowl shaped)
the point given is HIGHER than the vertex .... so this is bowl shaped
Vertex (h,k) = (0,2)
vertex form y = a(x-h)^2 + k
y = a (x-0)^2 + 2
\sub in the point given to calc 'a'
6 = a4^2 + 2
4 = 16a a = 1/4
y = 1/4x2 + 2
can i give u more questions to answer, just do it as fast as u can, u dont have to show the work
A parabola opening up or down has vertex (0,-3) an passes through (10,-8). Write its equation in vertex form
Just do it the same way I just did your first question......if you understand THAT answer , you can do this one with diferent numbers ......