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A parabola opening up or down has vertex (0,2) and passes through (4,6)

 Write its equation in vertex form.

 May 22, 2020
 #1
avatar+26806 
+1

vertex will be the high (mound shaped) or low point (bowl shaped)

 

the point given is HIGHER than the vertex    .... so this is bowl shaped 

 May 22, 2020
 #2
avatar+18 
0

but can u write it in its vertex form?

 May 22, 2020
 #3
avatar+26806 
+2

Vertex   (h,k)   =  (0,2)

 

vertex form   y = a(x-h)^2 + k

                     y = a (x-0)^2 + 2

\sub in the point given to calc 'a'

 

6 = a4^2 + 2

4 = 16a    a = 1/4

 

 

y = 1/4x2 + 2

ElectricPavlov  May 22, 2020
 #4
avatar+18 
0

can i give u more questions to answer, just do it as fast as u can, u dont have to show the work

A parabola opening up or down has vertex (0,-3) an passes through (10,-8). Write its equation in vertex form

 May 22, 2020
 #5
avatar+26806 
0

Just do it the same way I just did your first question......if you understand THAT answer , you can do this one with diferent numbers ......

ElectricPavlov  May 22, 2020

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