A parabola opening up or down has vertex (0,2) and passes through (4,6)

Write its equation in vertex form.

nicktheninz May 22, 2020

#1**+1 **

vertex will be the high (mound shaped) or low point (bowl shaped)

the point given is HIGHER than the vertex .... so this is bowl shaped

ElectricPavlov May 22, 2020

#2

#3**+2 **

Vertex (h,k) = (0,2)

vertex form y = a(x-h)^2 + k

y = a (x-0)^2 + 2

\sub in the point given to calc 'a'

6 = a4^2 + 2

4 = 16a a = 1/4

y = 1/4x^{2} + 2

ElectricPavlov
May 22, 2020

#4**0 **

can i give u more questions to answer, just do it as fast as u can, u dont have to show the work

A parabola opening up or down has vertex (0,-3) an passes through (10,-8). Write its equation in vertex form

nicktheninz May 22, 2020

#5**0 **

Just do it the same way I just did your first question......if you understand THAT answer , you can do this one with diferent numbers ......

ElectricPavlov
May 22, 2020