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# help i hate IXL, i have a ton of questions to ask

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A parabola opening up or down has vertex (0,2) and passes through (4,6)

Write its equation in vertex form.

May 22, 2020

#1
+26806
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vertex will be the high (mound shaped) or low point (bowl shaped)

the point given is HIGHER than the vertex    .... so this is bowl shaped

May 22, 2020
#2
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but can u write it in its vertex form?

May 22, 2020
#3
+26806
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Vertex   (h,k)   =  (0,2)

vertex form   y = a(x-h)^2 + k

y = a (x-0)^2 + 2

\sub in the point given to calc 'a'

6 = a4^2 + 2

4 = 16a    a = 1/4

y = 1/4x2 + 2

ElectricPavlov  May 22, 2020
#4
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can i give u more questions to answer, just do it as fast as u can, u dont have to show the work

A parabola opening up or down has vertex (0,-3) an passes through (10,-8). Write its equation in vertex form

May 22, 2020
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+26806
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Just do it the same way I just did your first question......if you understand THAT answer , you can do this one with diferent numbers ......

ElectricPavlov  May 22, 2020