The number of toy cars that Ray has is a multiple of 6. When he loses two of them, the number of cars that he has left is a multiple of n. If n is a positive even integer less than 10, then how many possible values are there for n?
If it is a multiple of six, and you are losing two of the cars, then the remaining number of cars will be divisible by two but not by six since it will not be divisible by three.
The first few values are 6, 12, 18, 24, 30, 36 which means 4, 10, 16, 22, 28, 34. The numbers four and eight work, so add two more.
Thus, there should be three values that will work.
